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-0.5x^2-0.34x+9=0
a = -0.5; b = -0.34; c = +9;
Δ = b2-4ac
Δ = -0.342-4·(-0.5)·9
Δ = 18.1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.34)-\sqrt{18.1156}}{2*-0.5}=\frac{0.34-\sqrt{18.1156}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.34)+\sqrt{18.1156}}{2*-0.5}=\frac{0.34+\sqrt{18.1156}}{-1} $
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